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01 | Curve Fitting Made Easy 🔥 | Module 5 VTU Mathematics | easy 6 marks
00:17:22
11| Fourier cosine  Transformation VTU / Non Vtu | Problems with solutions
00:10:41
10| Fourier Transformation VTU / Non Vtu | Problems with solutions
00:18:51
09 | Fourier sine  Transformation VTU / Non Vtu | Problems with solutions |
00:09:10
08 | Fourier cosine Transformation VTU / Non Vtu | Problems with solutions
00:17:01
07| e ^ |x| | Fourier Sine Transformation VTU / Non Vtu | Problems with solutions
00:13:31
06 | 1-|x| || Fourier Transformation VTU / Non Vtu | Problems with solutions
00:21:17
05 |f(x)=xe^x | Fourier Transformation VTU / Non Vtu | Problems with solutions |
00:18:32
04 | e power of mod of x  | Fourier Transformation VTU / Non Vtu | Problems with solutions
00:07:46
03 | Fourier Transformation VTU / Non Vtu | Problems with solutions
00:22:49
02 | 1- x2  | Fourier Transformation VTU / Non Vtu | Problems with solutions
00:33:11
01 | Fourier Transformation VTU / Non Vtu | Problems with solutions
00:19:49
Fourier Transformation Formulae Explained | Learn Half Range Fourier Series & Transform Concepts
00:12:33
04||Practical Harmonic Analysis | First Three Fourier Cosine Coefficients | Step-by-Step
00:14:23
03||Practical Harmonic Analysis | DC Component & First Harmonic Amplitude | Step-by-Step
00:19:46
02|| Practical Harmonic Analysis Example | Fourier Series up to Second Harmonic | type 2
00:20:03
01||Practical Harmonic Analysis Example | Compute Constant Term & First Two Harmonics |
00:26:54
Practical Harmonic Analysis Formulae | Learn Half Range Fourier Series Easily |
00:14:14
05||Half Range Fourier Sine Series | Proof that (l/2 − x) = (l/π) Σ (1/n) sin(2nπx/l) |
00:10:35
04 || Fourier Cosine Series of f(x) = (¼ − x), (x − ¾) | Half Range Fourier Series |VTU | Kannada
00:29:12
03 ||Half Range Fourier Sine Series of f(x) = x and π−x ||VTU || Kannada ||Ravinandiengg
00:16:21
02 || Half Range Fourier Cosine Series of f(x) = x sin x in (0, π) ||  Series ||Kannada
00:27:07
01 || Half Range Fourier Cosine Series of f(x) = π − x in (0, π) | | Kannada || VTU
00:13:06
Formula for  Half Range Fourier sine and cosine Series  | Fourier series | Engineering Mathematics 3
00:06:40
24 || Fourier Series of f(x) = x² in (−l, l) |  Engineering Mathematics  || ravinandiengg
00:13:38
23 || Fourier Series f(x) = 2x − x² in (0, 3) | Step-by-Step Solution | ravinandiengg
00:22:14
22 || FS f(x) = πx and π(2−x) | Derivation & Proof of π²/8 = Σ 1/(2n−1)² | Engineering Maths
00:15:35
21 || FS | f(x) = ±k | Step-by-Step Solution ||ravinandi engg ||
00:08:40
20 || Fourier Series for f(x)=1±(4x/3) | Step-by-Step Solution | VTU Engineering Maths |
00:19:36
19 || Fourier Series Derivation | f(x)=1 (0, π) and 0 (π, 2π) | VTU Exam 2025
00:13:23